Question

1) Consider the circuit shown in the figure. The battery has emf $varepsilon$ = 25 volts and negligible internal resistance. The inductance is $L$ = 0.80 H and the resistances are $R_1$ = 12.0 $Omega$ and $R_2$ = 9.0 $Omega$. Initially the switch $S$ is open and no currents flow. Then the switch is closed. i) What is the current in the resistor $R_1$ just after the switch is closed? a) 1.5 A b) 2.1 A c) 3.0 A d) 4.2 A e) 5.0 A

          1) Consider the circuit shown in the figure. The battery has emf $varepsilon$ = 25 volts and negligible internal resistance. The inductance is $L$ = 0.80 H and the resistances are $R_1$ = 12.0 $Omega$ and $R_2$ = 9.0 $Omega$. Initially the switch $S$ is open and no currents flow. Then the switch is closed.

i) What is the current in the resistor $R_1$ just after the switch is closed?
a) 1.5 A
b) 2.1 A
c) 3.0 A
d) 4.2 A
e) 5.0 A

1) Consider the circuit shown in the figure. The battery has emf varepsilon = 25 volts and negligible internal resistance. The inductance is L = 0.80 H and the resistances are R1 = 12.0 Omega and R2 = 9.0 Omega. Initially the switch S is open and no currents flow. Then the switch is closed.

i) What is the current in the resistor R1 just after the switch is closed?
a) 1.5 A
b) 2.1 A
c) 3.0 A
d) 4.2 A
e) 5.0 A

Added by Juan B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Darshan Maheshwari

03/22/2022

Step 1

Therefore, at the very moment the switch is closed, the inductor behaves like an open circuit. Show more…

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1) Consider the circuit shown in the figure. The battery has emf ε = 25 volts and negligible internal resistance. The inductance is L = 0.80 H and the resistances are R1 = 12.0 Ω and R2 = 9.0 Ω. Initially the switch S is open and no currents flow. Then the switch is closed. i) What is the current in the resistor R1 just after the switch is closed? a) 1.5 A b) 2.1 A c) 3.0 A d) 4.2 A e) 5.0 A