Question

1. Consider the coaxial cable in the figure below. The inner conductor has a radius of a. The outer conductor has an inner radius of b. The dielectric material between a and b has permittivity of ?. The cable has a length of l. A voltage is applied such that a charge Q+ accumulates uniformly on the outer surface of the inner conductor, and Q_ accumulates on the inner surface of the outer conductor. (a) In the region, a < r < b, show that the electric field \(\vec{E}\) is given by: \(\vec{E} = -\hat{r}\frac{Q_{+}}{2\pi\epsilon rl}\) Please start from either \(\nabla \cdot \vec{E} = \frac{\rho_v}{\epsilon}\) or \(\vec{E} = \frac{1}{4\pi\epsilon} \int_S \frac{\rho_s \vec{R}}{R^3} ds\). (b) The electric field \(\vec{E}\) in the region r < a. (c) The electric field \(\vec{E}\) in the region r > b.

          1. Consider the coaxial cable in the figure below. The inner conductor has a radius of a. The outer
conductor has an inner radius of b. The dielectric material between a and b has permittivity of ?. The
cable has a length of l. A voltage is applied such that a charge Q+ accumulates uniformly on the outer
surface of the inner conductor, and Q_ accumulates on the inner surface of the outer conductor.
(a) In the region, a < r < b, show that the electric field \(\vec{E}\) is given by: \(\vec{E} = -\hat{r}\frac{Q_{+}}{2\pi\epsilon rl}\)
Please start from either \(\nabla \cdot \vec{E} = \frac{\rho_v}{\epsilon}\) or \(\vec{E} = \frac{1}{4\pi\epsilon} \int_S \frac{\rho_s \vec{R}}{R^3} ds\).
(b) The electric field \(\vec{E}\) in the region r < a.
(c) The electric field \(\vec{E}\) in the region r > b.

1. Consider the coaxial cable in the figure below. The inner conductor has a radius of a. The outer
conductor has an inner radius of b. The dielectric material between a and b has permittivity of ?. The
cable has a length of l. A voltage is applied such that a charge Q+ accumulates uniformly on the outer
surface of the inner conductor, and Q accumulates on the inner surface of the outer conductor.
(a) In the region, a < r < b, show that the electric field E⃗ is given by: E⃗ = -r̂(Q+)/(2πϵ rl)
Please start from either ∇·E⃗ = ()/(ϵ) or E⃗ = (1)/(4πϵ)(R⃗)/(R^3) ds.
(b) The electric field E⃗ in the region r < a.
(c) The electric field E⃗ in the region r > b.

Added by Brandy N.

Question

Please give Ace some feedback