00:03
So the first set of questions here have to do with a video that was posted with the question.
00:11
And the video really does do a good job of illustrating what you should expect in this separation lab if you haven't taken a look at it.
00:20
But the reason that the mixture used in this video and what it sounds like you'll be using in the lab is called a ternary mixture is because it's made up of three substances.
00:31
And the compounds that are making up this ternary mixture happen to be salt, chalk, and sand.
00:43
And the chemical formulas used for these, the salt is actually sodium chloride, n -i -c -l.
00:50
The chalk is calcium carbonate, so c -a -c -o -3.
00:55
And the sand is silicon dioxide, so s -i -o -2.
01:02
Now the next part starts to talk about how the mixture is going to be separated.
01:07
And the first thing it appears you'll be doing in the lab is dissolving one of the substances in water.
01:14
So the substance in this list of three compounds that happens to be water soluble or can dissolve in water is the salt.
01:23
So after we dissolve the salt and filter the mixture through a mixture.
01:32
Funnel what should be left behind is just a mixture of the chalk and sand and the salt should be in the water that was filtered out through the filter paper um so now that you have the water um filtered out that contains the salt you want to get that um salt alone um so we need to go through some purification steps so in order to purify this salt solution so that only salt is left behind, it looks like the process of evaporation or boiling off the water is used in your lab.
02:21
Okay.
02:22
So now it moves into separating the chalk and the sand mixture.
02:27
And in order to do this, it looks like your lab will be utilizing another.
02:35
Technique to dissolve one of these substances using hydrochloric acid.
02:41
And we'll be looking at the reaction with the hydrochloric acid and how it dissolves one of these substances in the next set of questions.
02:54
But the chemical change that occurs is the reaction, the chemical reaction with hydrochoric acid.
03:06
That would be the step where there's a chemical change.
03:09
And it's actually this compound that dissolves the chalk or the calcium carbonate substance.
03:18
So now moving into the next set of questions, it looks like we need to balance a couple equations and then write out their ionic equations.
03:33
Okay, so this is the chemical reaction that occurs.
03:39
When the calcium carbonate is reacted with hydrochloric acid, as you'll be dealing in your lab.
03:47
So first thing we need to do is balance this chemical equation.
03:55
So first thing to do is to separate the equation into two sides so we can take inventory of the elements on each side.
04:07
So on my reactant side or left hand side, i have one calcium.
04:12
I have one carbon.
04:15
I have three oxygen.
04:21
I have one hydrogen.
04:26
I'm going to make it look like it's not a four.
04:28
And i also have one chlorine.
04:33
On my right side, i have one calcium again.
04:45
One carbon again.
04:51
Three oxygen again.
04:58
2 hydrogen and 2 chlorine.
05:13
So i'm going to go over to my reactant side and balance out my hydrogen and chlorine to start.
05:19
This gives me a total of 2 hydrogen now and 2 chlorine.
05:36
And this gives me a balanced chemical equation.
05:40
So now that the chemical equation is balanced, we can split it up into its ionic version.
05:47
So when we go to split this up into its ionic version, we have to take each compound and separate it into its constituent elements, the elements that make it up.
06:05
So we have calcium, which has a positive 2 charge, reacting with carbonate, which together has a 2 minus charge.
06:27
So carbonate is a polyatomic ion.
06:31
Now when we go to write our ions of hydrogen and chlorine, we have to take this coefficient into account.
06:40
So we'll have two hydrogen plus one ions and two chlorine minus one ions.
06:54
And that does it for my reactant side.
06:56
So now i'll move over to my products.
06:59
And on my product side, i'm going to split up my calcium chloride.
07:02
I have one calcium coming from this.
07:05
Compound, and that has a positive two charge again.
07:11
And based on the subscript, i have two chlorine minus one ions.
07:24
Moving on to carbon dioxide...