00:01
In the given question, mass of sodium hydroxide, that is n -a -o -h is given, equal to 3 .020 gram.
00:13
And the mass of carbon dioxide, that is co2, is given, 1 .062 gram.
00:22
We have to find the mass of sodium carbonate formed, that is, an a2, co3.
00:29
So first we have to write a balanced equation between sodium hydroxide and carbon dioxide, which is as n -o -h plus co2, and this gives an a2 -c -o -3 plus h2o.
00:54
So this is the complete balanced equation.
00:57
Now first we have to find the limiting reagent, which will decide the amount of product formation and for that we have to find the mole of each reactant by using the formula mole is equal to mass divided by molar mass so we will find the mole of reactant one by one starting with the mole of sodium hydroxide that is an ao which is equal to the mass that is given 3 .020 gram divided by the molar mass that is for 40 gram per mole.
01:34
When we solve this it will be equal to 0 .075 mole.
01:40
Now we will find the mall of carbon dioxide that is co2 and this is equal to the mass that is 1 .062 divided by molar mass that is 44 gram per mole.
01:56
When we solve this it will be equal to 0 .0241 mole...