1. Draw the structure of the alkyl chloride needed to...

Transcript

00:01 Hello everyone so according to the solution part we can write the structure p is going to give you the edge the structure of will be looking like this way it is having a two lone pair of electron along with that this is a c l it is having the ph over here one is having the edge so it's going to be reacted when it's going to be reacted with what is going to be happening so basically what we need to find out over here we need to draw the structure of alky is low right when it's going to be prepared each of the following bits reagent right so according to that we need to be calculated over here okay how we can sorry how we can draw this particular structure so this loan curve of electron is going to be acting over here okay when it's going to be acting over here this bond is getting shifted okay so what we are getting we are getting like this way both the thing is going to be co -jointed over here it's become that this thing will become the same as it is as it is okay ph ph over here once it's going to be donate something it will become a positive sign and over here the p is having the positive carrying sign and this is going to be cogented over here it's having a ph it's having the ph yeah it's having a g okay now what will be happening this one is getting shifted over here once they but that one is going to be shifted over here we can see when we are going to be doing the next step that a e2 and plus this is having a minus sign so this point is getting shifted over here basically it's going to be come this is not e and this is having a h only car hydrogen okay this is having a hydrogen only i can write like this way okay it is hydrogen over here so this is going to be come over here and this point is going to be shifted over there so what we are getting in the next step we can say that then in the very next step we are getting b double bond okay this is the thing which we are getting b double bond h and this will be ph the thing over here on the left and side that is remaining the same way ph p h so uh where the p h uh is nothing but c h to c l or we can say this is your alkali chloride okay or we can say like this way alkyl chloride this is forming or this is going to be formed in this way and the c h2 here the c h2 c l see as here and then when we are taking same as above when we are talking for the second we can write like this way same as above one same as above we can write this is going to be happened this will be my cl plus b double bond okay sorry double bond not it's a loan bear whole thrice this bond is getting shifted over here and this bond is going to be shifted here so when we are talking about this particularly what we are getting we can get in the next step it will be like this way this is b it's getting a positive sign b rise and this is your edge okay in the very next step what we are getting in the very next step when we are going to be yeah it will be plus o and e plus and this is minus is getting over here it's going to…

Question

1. Draw the structure of the alkyl chloride needed to prepare each of the following Wittig reagents: Ph Ph a) Ph P Ph H Ph b) Ph P Ph H

Question

1. Draw the structure of the alkyl chloride needed to prepare each of the following Wittig reagents: Ph Ph a) Ph P Ph H Ph b) Ph P Ph H

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