Question

1. Figure 1 shows the voltage across a capacitor used for a power electronic application. The capacitance value is 2.5µF. The capacitor has an equivalent resistance (ESR) of 10 m?. The dielectric of the capacitor has a thermal resistance of 0.2°C/W to the ambient. (A) Sketch the current waveform through the capacitor for one cycle. (B) Evaluate the losses in the capacitor. (C) Evaluate the temperature rise in the dielectric of the capacitor. August 8, 2024 NIT Calicut 37 $I_{rms}^2$ 10779 $I_{rms}$ 103.8A Loss 107.8W ESR $R_{th}$ Temperature Rise 0.01? 0.2°C/W 21.6°C

          1. Figure 1 shows the voltage across a capacitor used for a power electronic application. The capacitance value is 2.5µF. The capacitor has an equivalent resistance (ESR) of 10 m?. The dielectric of the capacitor has a thermal resistance of 0.2°C/W to the ambient.
(A) Sketch the current waveform through the capacitor for one cycle.
(B) Evaluate the losses in the capacitor.
(C) Evaluate the temperature rise in the dielectric of the capacitor.
August 8, 2024
NIT Calicut
37
$I_{rms}^2$
10779
$I_{rms}$
103.8A
Loss
107.8W
ESR
$R_{th}$
Temperature Rise
0.01?
0.2°C/W
21.6°C

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1. Figure 1 shows the voltage across a capacitor used for a power electronic application. The capacitance value is 2.5µF. The capacitor has an equivalent resistance (ESR) of 10 m?. The dielectric of the capacitor has a thermal resistance of 0.2°C/W to the ambient.
(A) Sketch the current waveform through the capacitor for one cycle.
(B) Evaluate the losses in the capacitor.
(C) Evaluate the temperature rise in the dielectric of the capacitor.
August 8, 2024
NIT Calicut
37
Irms^2
10779
Irms
103.8A
Loss
107.8W
ESR
Rth
Temperature Rise
0.01?
0.2°C/W
21.6°C

Added by Carolina S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ze-Han Lee

08/19/2019

Step 1

Step 1: The current through the capacitor is given by: $$I_c = C \frac{dV}{dt}$$ where: * $I_c$ is the current through the capacitor * $C$ is the capacitance * $\frac{dV}{dt}$ is the rate of change of voltage across the capacitor Show more…

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1. Figure 1 shows the voltage across a capacitor used for a power electronic application. The capacitance value is 2.5µF. The capacitor has an equivalent resistance (ESR) of 10 mΩ. The dielectric of the capacitor has a thermal resistance of 0.2°C/W to the ambient. (A) Sketch the current waveform through the capacitor for one cycle. (B) Evaluate the losses in the capacitor. (C) Evaluate the temperature rise in the dielectric of the capacitor. V August 8, 2024 400V 30 40 50 5 10 15 20 25 60 Time in mS 400V 200A 1 15 20 30 5 NIT Calicut 37 t 50 60 Time in mS 50π Α Ims 10779 Irms 103.8A ESR Rth Loss 107.8W Temperature Rise 0.01Ω 0.2°C/W 21.6°C

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