00:01
In question, we have to find k in the terms of rho, l, r and t.
00:09
Okay.
00:09
So, to find this number of variable are here that is equal to 5.
00:18
That is k, rho, l, r and t.
00:21
This is 5 variable here.
00:23
Okay.
00:23
So number of primary variables that is given in the question that is 4 because these are m, l, theta and t.
00:40
So k dimension that is equal to m, l divided by theta t cube and the dimension of length that is capital l dimension of r that is l square by t square theta and t dimension is here theta and row dimension is ml per cube.
01:07
Okay.
01:08
So number of from this number of pi 5 groups that is equal to n minus m so this is equal to 1.
01:24
Okay so arbitrary constant that is equal to 1 so by comparing both sides this is k rho l r t this is k multiply rho a b c and d this is equal to m 0 0 and this.
01:43
Okay, so by comparing both sides the coefficient by putting the coefficient of all of these the coefficient of k that is equal to m1 l1 theta minus 1 t minus 3 and power 1 okay, row coefficient that is equal to m l minus 3 and power k l coefficient l power t and the next is l square t minus 2 theta minus 1 and coefficient is c here.
02:12
C coefficient is theta that is c.
02:15
So this is equal to this one.
02:18
Okay.
02:19
So from here by comparing comparing coefficient of coefficient on both sides of m l and c and theta.
02:33
So by comparing the coefficient of m that is equal to from here 1 from here a.
02:39
1 plus a that is is equal to 0.
02:42
From here, we got a is equal to minus 1.
02:46
Okay, a is equal to minus 1.
02:49
Next, we compare 1 plus for l, b minus 3a plus 2c...