1) Find the zeros of the following quadratic function: f(x) = x² – x – 12 2) Find all the real zeros of the polynomial function f(x) = x? – 16x³ + 64x 3) Describe the right-hand and the left-hand behavior of the graph of (Multiple choice) q(x) = –5x? + 12x³ + 13 a. Because the degree is even and the leading coefficient is negative, the graph falls to the left and rises to the right. b. Because the degree is even and the leading coefficient is negative, the graph rises to the left and falls to the right. c. Because the degree is even and the leading coefficient is negative, the graph falls to the left and falls to the right. d. Because the degree is odd and the leading coefficient is negative, the graph rises to the left and rises to the right. e. Because the degree is even and the leading coefficient is negative, the graph rises to the left and rises to the right.
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To find the zeros of the quadratic function, we need to set the function equal to zero and solve for x: f(x) = x^2 - 12 0 = x^2 - 12 Now, we can solve for x: x^2 = 12 x = ±√12 So, the zeros of the quadratic function are: x = ±√12 2) Show more…
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