00:01
For a confidence level of 96%, find the critical value for a normally distributed variable.
00:06
The sample mean is normally distributed if the population standard deviation is known.
00:10
So if we know the population standard deviation, the critical value for a 96 % confidence is going to be 2 .05.
00:23
You intend to estimate a population mean with a confidence interval.
00:27
You believe the population of a normal distribution.
00:29
Your sample size is 7.
00:32
Find the critical value that corresponds to a confidence level of 98%.
00:38
So this is going to be a t value.
00:41
It's going to be t of 0 .02 divided by 2 with a degree of freedom of 6, and that's 3 .143.
00:51
For 3, you measure 27 textbooks and you find that they have a mean weight of 52 ounces, assume the population standard deviation is 7 .7 ounces.
01:04
Constructed 95 % confidence interval.
01:10
So we will take 52 plus or minus 1 .96 times 7 .7 divided by the square root of 27...