00:02
Dear students, the reaction is given here a plus b gives rise to c plus d and the rate information is given with respect to the concentration of the reactants a and b.
00:13
So, here we have to find out the order of the reaction with respect to a and b and overall reaction order and we have to determine the rate constant also.
00:28
Along with that, we have to write the rate law expression.
00:30
So, let us first derive, determine the order of the reaction with respect to each reactant.
00:38
So let us assume here the rate law r equal to rate constant k a to the power x and b to the power y on which order, on which exponent it depends we do not know.
00:52
So let us take the orders with respect to the concentration terms a and b as x and y.
00:58
Therefore, in the first case, let us apply the first one r1 equal to rate constant k concentration of a let us take 0 .4 first one 0 .40 to the power x and 0 .20 to the power y and rate is how much 0 .12.
01:20
Then this is one equation.
01:24
Then we can take another equation r2 equal to k taking this one 0 .20 to the power x 0 .20 to the power y equal to 0 .03.
01:44
So this is the second equation.
01:46
Then applying it to the third equation also, we will get r3 equal to k 0 .60 to the power x 0 .40 to the power y equal to 0 .54.
02:02
Now equation 1 by 2, equation 1 by 2 implies this will cancel up.
02:12
So k k will cancel and we will get 0 .40 divided by 0 .20 to the power x equal to 0 .12 and this is 0 .03.
02:25
So this is 2 to the power x equal to 4 equal to 2 to the power 2 implies x equal to 2...