Given:
Length of pendulum, L = 2.00 m
Mass, m = 0.400 kg
Acceleration due to gravity, g = 9.8 m/s^2
Using the formula for the period of a pendulum:
\[ T = 2\pi \sqrt{\frac{L}{g}} \]
Substitute the given values:
\[ T = 2\pi \sqrt{\frac{2.00}{9.8}} \]
\[ T = 2\pi
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