1 hf molecule exhibits ir absorption at a wavenumber of 4250 cm 1 due to the an 1 transition cal

Name: 1 hf molecule exhibits ir absorption at a wavenumber of 4250 cm 1 due to the an 1 transition calculate the population of the first excited vibrational states at 300 k relative to the ground 84587
Uploaded: 2022-07-27T12:03:05-08:00
Duration: 3 min 49 s
Channel: Madhur L
Description: 1 hf molecule exhibits ir absorption at a wavenumber of 4250 cm 1 due to the an 1 transition calculate the population of the first excited vibrational states at 300 k relative to the ground 84587

Question

1. HF molecule exhibits IR absorption at a wavenumber of 4250 cm-¹ due to the An = +1 transition. Calculate the population of the first excited vibrational states at 300 K relative to the ground vibrational state using simple harmonic potential model. A) 2.62e-6 B) 2.42e-3 C) 2.42e-5 D) 6.56e-7 E) 1.47e-9

          1. HF molecule exhibits IR absorption at a wavenumber of 4250 cm-¹ due to the An = +1
transition. Calculate the population of the first excited vibrational states at 300 K
relative to the ground vibrational state using simple harmonic potential model.
A) 2.62e-6
B) 2.42e-3
C) 2.42e-5
D) 6.56e-7
E) 1.47e-9

1 hf molecule exhibits ir absorption at a wavenumber of 4250 cm 1 due to the an 1 transition calculate the population of the first excited vibrational states at 300 k relative to the ground 84587

Added by Christian M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

07/27/2022

Step 1

Step 1: The population of the first excited vibrational state relative to the ground vibrational state is given by: $$N_1/N_0 = exp(-E_1/kT)$$ where: * $N_1$ is the population of the first excited vibrational state * $N_0$ is the population of the ground Show more…

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1. HF molecule exhibits IR absorption at a wavenumber of 4250 cm-¹ due to the An = +1 transition. Calculate the population of the first excited vibrational states at 300 K relative to the ground vibrational state using simple harmonic potential model. A) 2.62e-6 B) 2.42e-3 C) 2.42e-5 D) 6.56e-7 E) 1.47e-9