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1 homework point(s) pH of Aqueous Sulfuric Acid Calculate the pH of a 5.10$\times$10$^{-3}$ M solution of H$_2$SO$_4$. ($K_a$ = 0.0120 for HSO$_4^-$) 1.471 HSO$_4^-$ is not that acidic. H$_2$SO$_4$ is a strong acid and is also diprotic. The first H$^+$ dissociates completely. The equilibrium position for the dissociation of the second H$^+$ must be calculated. Copyright: Department of Chemistry, Simon Fraser University - © SFU Chemistry 2000-2024

          1 homework point(s)
pH of Aqueous Sulfuric Acid
Calculate the pH of a 5.10$\times$10$^{-3}$ M solution of H$_2$SO$_4$.
($K_a$ = 0.0120 for HSO$_4^-$)
1.471
HSO$_4^-$ is not that acidic.
H$_2$SO$_4$ is a strong acid and is also diprotic. The first H$^+$ dissociates completely. The equilibrium position for the dissociation of the second H$^+$ must be
calculated.
Copyright: Department of Chemistry, Simon Fraser University - © SFU Chemistry 2000-2024

1 homework point(s)
pH of Aqueous Sulfuric Acid
Calculate the pH of a 5.10×10^-3 M solution of H2SO4.
(Ka = 0.0120 for HSO4^-)
1.471
HSO4^- is not that acidic.
H2SO4 is a strong acid and is also diprotic. The first H^+ dissociates completely. The equilibrium position for the dissociation of the second H^+ must be
calculated.
Copyright: Department of Chemistry, Simon Fraser University - © SFU Chemistry 2000-2024

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Adi S

07/21/2023

Step 1

Therefore, the initial concentration of H⁺ is 5.10 × 10⁻³ M. Show more…

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1 homework point(s) pH of Aqueous Sulfuric Acid Calculate the pH of a 5.10×10⁻³ M solution of H₂SO₄. ($K_a$ = 0.0120 for HSO₄⁻) 1.471 HSO₄⁻ is not that acidic. H₂SO₄ is a strong acid and is also diprotic. The first H⁺ dissociates completely. The equilibrium position for the dissociation of the second H⁺ must be calculated. Copyright: Department of Chemistry, Simon Fraser University - © SFU Chemistry 2000-2024