00:01
In this problem, we are given that there is a binomial distribution such that the mean of the distribution, that's equal to 5 and the variance.
00:11
This is equal to 10 by 3.
00:13
And we have to get the value of n of this distribution, which basically represents the number of independent trials.
00:19
So first, we consider the probability of the success to be represented by p and the probability of the failure to be represented by q.
00:26
And using this formula, we see that when we multiply n with p, this gives us the value of the mean, which is given to us as 5.
00:35
And using this formula, when we multiply n p and q together, this gives the variance, which is 10 by 3.
00:42
So let's take the value of n times p from the first equation and put it into the second equation.
00:47
So doing that, we get 5 times q equal to 10 by 3...