Question

1) In a horizontal block-spring system m = 0.3 kg and k = 5 N/m. At t = 0.1 s, the velocity is v = -0.15 m/s and the acceleration a = +0.85 m/s^2. Find: [4p] (a) An expression for the displacement as a function of time, x(t). (b) The times in the first cycle when IvI = 0.5Vmax, where Vmax is the maximum speed

Name: 1 in a horizontal block spring system m 03 kg and k 5 nm at t 01 s the velocity is v 015 ms and the acceleration a 085 ms2 find 4p a an expression for the displacement as a function of time 87603
Uploaded: 2023-01-29T05:22:59-08:00
Duration: 1 min 19 s
Channel: Aarya B
Description: 1 in a horizontal block spring system m 03 kg and k 5 nm at t 01 s the velocity is v 015 ms and the acceleration a 085 ms2 find 4p a an expression for the displacement as a function of time 87603

          1) In a horizontal block-spring system m = 0.3 kg and k = 5 N/m. At t = 0.1 s, the
velocity is v = -0.15 m/s and the acceleration a = +0.85 m/s^2. Find: [4p]
(a) An expression for the displacement as a function of time, x(t).
(b) The times in the first cycle when IvI = 0.5Vmax, where Vmax is the maximum
speed

1 in a horizontal block spring system m 03 kg and k 5 nm at t 01 s the velocity is v 015 ms and the acceleration a 085 ms2 find 4p a an expression for the displacement as a function of time 87603

Added by Christopher C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aarya B

01/29/2023

Step 1

$\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{5}{0.3}} = \sqrt{\frac{50}{3}} \approx 4.082 \, rad/s$ Show more…

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1) In a horizontal block-spring system m = 0.3 kg and k = 5 N/m. At t = 0.1 s, the velocity is v = -0.15 m/s and the acceleration a = +0.85 m/s^2. Find: [4p] (a) An expression for the displacement as a function of time, x(t). (b) The times in the first cycle when IvI = 0.5Vmax, where Vmax is the maximum speed