Question

1. In each part,evaluate the int egral giventh \[ f(x)=\left\{\begin{array}{l} |x+2|, \text { if } x \geq 0 \\ x+2, \text { if } x<0 \end{array}\right. \] a. $ \int_{-2}^{0} f(x) d x $ c. $ \int_{0}^{6} f(x) d x $ b. $ \int_{-2}^{2} f(x) d x $ d. $ \int_{-4}^{6} f(x) d x $

          1. In each part,evaluate the int egral giventh
\[
f(x)=\left\{\begin{array}{l}
|x+2|, \text { if } x \geq 0 \\
x+2, \text { if } x<0
\end{array}\right.
\]
a. \( \int_{-2}^{0} f(x) d x \)
c. \( \int_{0}^{6} f(x) d x \)
b. \( \int_{-2}^{2} f(x) d x \)
d. \( \int_{-4}^{6} f(x) d x \)

$1. In each part,evaluate the int egral giventh f(x)={ |x+2|, if x ≥ 0 x+2, if x<0 . a. ∫-2^0 f(x) d x c. ∫0^6 f(x) d x b. ∫-2^2 f(x) d x d. ∫-4^6 f(x) d x$

Added by Felipe R.

Calculus Early Transcendentals

Howard Anton, Irl Bivens, Stephen Davis 9th Edition

Chapter 5

Instant Answer

Solved by Expert Ekaveera Kumar

12/22/2020

Step 1

To evaluate $ \int_{-2}^{0} f(x) d x $, we need to split the integral into two parts: one for $ x < 0 $ and one for $ x \geq 0 $. For $ x < 0 $, the function is $ f(x) = x + 2 $. So the integral becomes: \[ \int_{-2}^{0} (x + 2) d x \] Integrating Show more…

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