1) In Stat Key under Bootstrap Confidence Intervals for a difference in proportions, there is a data set “student survey: smoke by gender”. This gives the proportion of male students and female students who smoked based on a student survey at another college. Generate enough bootstrap distributions so that the bell-shape appears. a. Use the standard error formula to find a 95% confidence interval for the difference in population proportions of female students who smoke and male students who smoke. Type in the work (so I can see the values for the mean and standard error). Then type out the interpretation of the interval. [3] b. Is the number zero inside your confidence interval? What does this suggest about being able to conclude there is a difference in the population proportions? [2]
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Let's assume we have the following data: - Proportion of male students who smoked: p1 = 0.25 - Proportion of female students who smoked: p2 = 0.15 - Sample size for male students: n1 = 200 - Sample size for female students: n2 = 200 Show more…
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Use the standard error formula to find a 95% confidence interval for the difference in population proportions of female students who smoke and male students who smoke. Type in the work (so I can see the values for the mean and standard error). Then type out the interpretation of the interval. Mean = -0.046 SE = 0.033 -0.046 ± 0.033(2) = (-0.112, 0.02) We are 95% sure that the difference in population proportions of female students who smoke and male students who smoke is between -0.112 and 0.02. Is the number zero inside your confidence interval? What does this suggest about being able to conclude there is a difference in the population proportions?
Dominador T.
1. A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55. Determine the 99% confidence interval for the population mean. (Round your answers to 2 decimal places.) Confidence interval for the population mean is and . A research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. They found the distribution of amounts spent per week followed the normal distribution with a population standard deviation of $5. A sample of 64 steady smokers revealed that X=$20. a. What is the 95% confidence interval estimate of ? (Round your answers to 3 decimal places.) Confidence interval is between $ and $ .
Jason G.
1. A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55. Determine the 99% confidence interval for the population mean. (Round your answers to 2 decimal places.) Confidence interval for the population mean is and . 2. A research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. They found the distribution of amounts spent per week followed the normal distribution with a population standard deviation of $5. A sample of 64 steady smokers revealed that . a. What is the 95% confidence interval estimate of ? (Round your answers to 3 decimal places.) Confidence interval is between $ and $ .
Kari H.
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