1. In the circuit besides, the diode is: (a) Unbiased (b)...

1. In the circuit besides, the diode is: (a) Unbiased (b) Reverse-biased (c) Forward-biased (d) None of the above. 2. In the circuit below, the voltage difference across the diode is: (a) 10 V (b) 0 (c) 0.7 V (d) Unspecified. 3. The current through the diode in the circuit besides is: (a) Non-zero downwards (b) Non-zero upwards (c) 0 (d) None of the above.

Transcript

00:01 High in this circuit we are given with a diode and this is the input voltage.

00:05 So suppose here we have the input voltage is 5 volt and the voltage at the another end is 8 volt.

00:13 So in this case we have v input is less than the other voltage v.

00:19 Therefore the diode will be reverse biased in this case since the input voltage is smaller than the other voltage.

00:30 Reverse biased so this is the first circuit in the next question we are given with a second circuit so here using the nodal analysis so using the nodal analysis we have to find the voltage across the diode so here this point let it be some g so g is grounded now using nodal analysis we have vd minus 10 divided by 10 plus here there is a negative connected to the resistor so this quantity will be plus 20 volt divided by 10 so this is the resistance value which is equal to vd minus 0 divided by rf so rf is the forward resistance of the diode so rf is rf is the forward resistance of the diode so rf is or rf is the forward resistance of the tire.

01:35 Therefore in both the cases we have vd as common.

01:37 So vd will be equal to.

01:39 So this will be 1 by 5.

01:42 And this is minus 1 by rf.

01:47 So taking this to the lhs and equating to 0.

01:50 So this is the quantity minus 1 plus 2 which will be equal to 0.

01:55 Or vd into.

01:59 So taking the reciprocal or lcm, vd minus 5 divided by 5 into rf, minus or plus 1 is equal to 0 or vd into rf minus 5 divided by phi rf is equal to minus 1 or vd will be equal to so taking the reciprocal of this quantity and while going it to the right hand side so this will be equal to phi rf divided by so taking the negative sine inverse that is five minus rf so this is the diode voltage here for ideal case, the resistance across the diode rf will be equal to 0.

02:45 So this is for ideal case...

Question

Please give Ace some feedback