00:01
Redox reaction is short for oxidation reduction reaction which always come in pair.
00:07
In this problem, we're given with the reaction that we will find the following.
00:17
So this reaction is redox reaction.
00:20
As we will see later, that this involves loss or gain of electrons as evident from the change in the oxidation stage of the species.
00:29
From the change in the oxidation state of the species, we will be able to find the following.
00:35
So letter a, the element that is oxidized.
00:41
For letter b, the element that is reduced.
00:46
And if we know what the elements are, then we will be able to know the oxidation, or rather the oxidizing agent.
00:55
That's what we will find in letter c.
00:59
And for letter d, the reducing agent.
01:02
And finally, we will be establishing the direction of electron flow.
01:11
So letter e is direction of electron flow.
01:19
So let us investigate the oxidation states.
01:23
So let's start with carbon.
01:29
So carbon in c2h60 as the following oxidation state.
01:35
So it's right here our solution.
01:39
C in c2h60.
01:44
So let us take note that common oxidation states of these elements in their compound in compound form are as follows.
01:54
So h is positive 1 and o is negative 2.
01:57
So carbon, on the other hand can have variable oxidation states which we will find here.
02:02
So you have 2c plus h plus o.
02:07
The sum of their oxidation states must be 0 since c2h6 is tetra.
02:11
So t2c plus 6 times 1 plus negative 2 equals 0.
02:17
This gives us c equal to negative 2...