Question

"1 kg of molten lead at its melting point of 327°C is dropped in 1 kg of water at 20°C. Assuming no heat is lost; calculate the final temperature of water. (Sp. heat cap. of lead = 130 J/kg°C, Sp. latent heat of fusion of lead = 27000 J/g, Sp. heat cap. of water = 4200 j/kg°C)"

Name: 1 kg of molten lead at its melting point of 327c is dropped in 1 kg of water at 20c assuming no heat is lost calculate the final temperature of water sp heat cap of lead 130 jkgc sp latent heat of fus
Uploaded: 2022-01-12T15:19:00-08:00
Duration: 3 min 28 s
Channel: Dinesh Chand Jangid
Description: 1 kg of molten lead at its melting point of 327c is dropped in 1 kg of water at 20c assuming no heat is lost calculate the final temperature of water sp heat cap of lead 130 jkgc sp latent heat of fus

          "1 kg of molten lead at its melting point of 327°C is dropped in 1 kg of water at 20°C. Assuming no heat is lost; calculate the 
final temperature of water. (Sp. heat cap. of lead = 130 J/kg°C, Sp. latent heat of fusion of lead = 27000 J/g, Sp. heat cap. of
 water = 4200 j/kg°C)"

Added by Anuj C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Dinesh Chand Jangid

01/12/2022

Step 1

Step 1: Calculate the heat lost by the lead when it changes state: \(Q_{\text{lost}} = (m_{\text{lead}} \times L) + (m_{\text{lead}} \times C_{\text{lead}} \times \Delta T)\) \(Q_{\text{lost}} = (1 \, \text{kg} \times 27000 \, \text{J/g}) + (1 \, \text{kg} \times Show more…

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"1 kg of molten lead at its melting point of 327°C is dropped in 1 kg of water at 20°C. Assuming no heat is lost; calculate the final temperature of water. (Sp. heat cap. of lead = 130 J/kg°C, Sp. latent heat of fusion of lead = 27000 J/g, Sp. heat cap. of water = 4200 j/kg°C)"