00:01
P of w is greater than or equals to 3 divided by p of x is equals to minus 2 plus p of w is less than minus 1 divided by p of x is equals to 2.
00:19
Now this we can also write it as 1 minus p of w is less than 3 divided by 1 minus q plus p of w less than minus 1 divided by q.
00:38
So here w belongs to n 1 comma 2 where z is equals to w minus 1 divided by under root 2 this follows the normal distribution 0 comma 1.
00:56
So now p of w less than 3 this is equals to p of w minus 1 divided by under root 2 which is less than 3 minus 1 divided by under root 2.
01:11
So this will get p of z less than under root 2 and this will be phi of root 2.
01:26
So p of w less than minus 1 is equals to p of w minus 1 divided by under root 2 less than minus 1 minus 1 divided by under root 2.
01:40
So this will get p of z less than minus under root 2 which is again 1 minus phi of root 2.
01:51
So now 1 minus p of w less than 3 this is equals to 1 minus phi of under root 2.
02:07
So here this is also equals to phi of minus under root 2.
02:13
Now p of w less than minus 1 this is equals to 1 minus phi of under root 2 which is equals to phi of minus under root 2.
02:29
Now decoding error the decoding error this will be phi of minus under root 2 divided by 1 minus q plus phi of minus under root 2 divided by q...