Since point P(T, y, 2) is equidistant from points (1, -1, 0) and (-1, 2, 1), we can set up the distance formula for both distances and set them equal to each other:
$[(T-1)^2 + (y+1)^2 + (2-0)^2] = [(T+1)^2 + (y-2)^2 + (2-1)^2]$
Now, we can simplify and solve
Show more…