00:01
Hi, i'm david and i'm here to help you and change your question.
00:03
Now let me bring up your question here.
00:06
In the question here, we are going to discuss about the mean square error of the estimator.
00:12
We know that the mean square error is equal to the variance of the estimator, then we plus one the bias of the estimator is totally square.
00:26
And we have the bias of the estimator, it will equal to the e of the theta heart with minus with the theta.
00:36
Now we have two questions, so let me split into the two screens, to the two equal parts.
00:43
Now the first estimate the y1, it will equal to the x1 plus x2 over 3.
00:53
And we are given the mean and the variance here.
00:57
So first of the form, for this one, i have to find e of the y1.
01:02
Equal to the e of the x1 plus the x2 over 3 and then get equal to the out of 3 e on the x1 plus e on the x2 and because they are the same so therefore we will have mean we equal to the 3 plus 3 and equal to the divided by 3 and then then get equal to the 3 and therefore this one here sorry it will be 6 divided be 3 equal to the 2.
01:35
And from here we can find the bias of the y1 equal to the 2.
01:42
The 2 will minus the mean will be the 3 and then we get equal to the minus 1.
01:47
And also we have to find the variance of the y1, just equal to the variance of the x1 plus the x2, divided by 3.
01:59
And then we get equal to we're born to bring the constant outside the variance.
02:03
We need to square.
02:04
Up so will be the three square variance of the x1 plus the variance of the x2 because they're independent and then we get equal to variance equal to the zbon 5 square plus 0 .05 square over the 9.
02:21
Then we have 0 .25 times 2 equal to the 715...