00:01
So we know that the angular separation between the bright fringes and the bright fringe in the middle is given by this equation.
00:11
And the angular separation between dark fringes and the bright fringe in the middle is given by this equation.
00:18
So in the question, we know the wavelength and we know the distance between the two slits.
00:28
So we can use for the first part for part a, we want to find out what is the angle that locates the dark fringe for m equals 0.
00:41
So i'm going to use a sign of theta equal to m plus 1 over 2 times lambda over d.
00:52
So to find theta, i need to say here, theta is equal to to inverse sign of m plus 1 over 2 divided by d times lambda.
01:10
So m is equal to 0, lambda is equal to 520 nanometer, and d is equal to 1 .4 times 10 to minus 6.
01:25
So theta would be equal to inverse sign of 520 divided by 2 times 1 .4 times 10 to the minus 6.
01:44
So at the same time, this is 920 nanometer...