Question

1. Limestone stalactites and stalagmites are formed in caves by the following reaction: Ca2+ (aq) + 2 HCO3- --> CaCO3 (s) + CO2 (g) + H2O (g) If 2.15 moles of calcium carbonate form at 298K under one atmosphere pressure, What is the total volume of gaseous product produced?

Name: 1 limestone stalactites and stalagmites are formed in caves by the following reaction ca2 aq 2 hco3 caco3 s co2 g h2o g if 215 moles of calcium carbonate form at 298k under one atmosphere pr 91874
Uploaded: 2021-10-13T07:54:26-08:00
Duration: 2 min 23 s
Channel: Taimoor Shabbir
Description: 1 limestone stalactites and stalagmites are formed in caves by the following reaction ca2 aq 2 hco3 caco3 s co2 g h2o g if 215 moles of calcium carbonate form at 298k under one atmosphere pr 91874

          1. Limestone stalactites and stalagmites are formed in caves by
the following reaction:
Ca2+ (aq) + 2
HCO3-  --> CaCO3 (s)
+ CO2 (g) + H2O (g)
If 2.15 moles of calcium carbonate form at 298K under one
atmosphere pressure, What is the total volume of gaseous product
produced?

Added by John S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Taimoor Shabbir

10/13/2021

Step 1

Given that 2.15 moles of calcium carbonate form, according to the reaction, 1 mole of calcium carbonate produces 1 mole of carbon dioxide and 1 mole of water vapor. Therefore, 2.15 moles of calcium carbonate will produce 2.15 moles of carbon dioxide and 2.15 moles Show more…

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1. Limestone stalactites and stalagmites are formed in caves by the following reaction: Ca2+ (aq) + 2 HCO3- --> CaCO3 (s) + CO2 (g) + H2O (g) If 2.15 moles of calcium carbonate form at 298K under one atmosphere pressure, What is the total volume of gaseous product produced?