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1. Microwave ovens work by irradiating food with microwave radiation. Microwaves are absorbed by polar molecules in food (mostly water) and physically rotate. The increased rotation is an increase in kinetic energy which increases the temperature of the food. a. Assuming that radiation with λ = 15.0cm is used, that all of the microwaves are absorbed and converted to heat, how many photons are necessary to melt a 10.0g ice cube at -5°C, and raise the temperature of the melted ice to 25°C (room temperature). Hot tip: you need to convert the wavelength to energy. 

          1.      Microwave ovens work by irradiating food with microwave radiation. Microwaves are absorbed by polar molecules in food (mostly water) and physically rotate. The increased rotation is an increase in kinetic energy which increases the temperature of the food. a.      Assuming that radiation with λ = 15.0cm is used, that all of the microwaves are absorbed and converted to heat, how many photons are necessary to melt a 10.0g ice cube at -5°C, and raise the temperature of the melted ice to 25°C (room temperature). Hot tip: you need to convert the wavelength to energy.
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Chemistry: The Central Science in SI Units, Global Edition
Chemistry: The Central Science in SI Units, Global Edition
Theodore L. Brown, Matthew W. Stoltzfus,… 14th Edition
Chapter 6
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1. Microwave ovens work by irradiating food with microwave radiation. Microwaves are absorbed by polar molecules in food (mostly water) and physically rotate. The increased rotation is an increase in kinetic energy which increases the temperature of the food. a. Assuming that radiation with λ = 15.0cm is used, that all of the microwaves are absorbed and converted to heat, how many photons are necessary to melt a 10.0g ice cube at -5°C, and raise the temperature of the melted ice to 25°C (room temperature). Hot tip: you need to convert the wavelength to energy.
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Microwave ovens work by irradiating food with microwave radiation. Microwaves are absorbed by polar molecules in food (mostly water) and physically rotate. The increased rotation is an increase in kinetic energy which increases the temperature of the food. a. Assuming that radiation with λ = 15.0cm is used, that all of the microwaves are absorbed and converted to heat, how many photons are necessary to melt a 10.0g ice cube at -5°C, and raise the temperature of the melted ice to 25°C (room temperature). b. Which of the following molecules would also absorb microwave radiation: phosphorus pentachloride, SiCl4, nitrogen triiodide, benzene. Draw Lewis structures to support your answer.

Sri K.
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Microwave ovens have become popular in kitchens everywhere. They are also used in the laboratory, particularly in drying samples for chemical analysis. A typical microwave oven uses radiation with a 12.2 cm wavelength. a. How many moles of photons of this radiation are required to raise the temperature of 345 g of water from 26.5 ºC to 99.8 ºC? b. The watt is a unit of power—the rate at which energy is delivered or consumed: 1 W = 1 J/s. Assume that all the energy of a 700 W microwave oven is delivered to the heating of water described in (a). How long will it take to heat the water?

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Microwave ovens use microwave radiation to heat food. The energy of the microwaves is absorbed by water molecules in food and then transferred to other components of the food. (a) Suppose that the microwave radiation has a wavelength of $10 \mathrm{~cm} .$ How many photons are required to heat $200 \mathrm{~mL}$ of water from 25 to $75^{\circ} \mathrm{C} ?$ (b) Suppose the microwave's power is $1000 \mathrm{~W}$ ( 1 watt $=1$ joule-second $) .$ How long would you have to heat the water in part (a)?

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Transcript

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00:01 To compare this question, we have wavelength of the radiation, microwave radiation is given 15 centimeters.
00:09 So here we have to calculate the amount number of photons.
00:15 Number of photons required to change 10 grams of ice to which is at minus 5 degrees celsius.
00:28 So water at 25 degrees celsius.
00:31 Celsius, we have to find out how much energy is required and then we can calculate the number of protons.
00:38 So here, energy of one photon, one photon is equal to hc divided by lambda.
00:51 H is 6 .626 multiplied by 10 power minus 34 joules per second.
00:57 And this c is 3 multiplied by 10 power 8 meters per second is a wave speed of light.
01:06 And this one is centimeters in centimeters it is given.
01:10 So multiplied by 10 minus 2 meters we will get here.
01:13 So this one is equal to multiplied by 10 power minus 2.
01:17 Then the energy of the photon.
01:19 One photon is 1 .3 to 5 multiplied by 10 power minus 24.
01:25 Jouz is the energy of the photon.
01:27 Done.
01:28 Now here the conversion of ice.
01:31 So 10 grams of ice which is at minus 5 degrees celsius, we have to convert this one to ice at zero degrees celsius...
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