1. NaNH2 Select to Draw 2. CH3Br HCI (1 equiv) OsO4 (catalytic) NMO Select to Draw Select to Draw
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Treatment with NaNH2 (a strong base) will deprotonate the alkyne, forming an acetylide anion. Subsequent reaction with CH3Br (methyl bromide) will alkylate the acetylide, adding a methyl group to the alkyne. This results in a terminal alkyne with a methyl group Show more…
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