00:01
Consider the free body diagram and observe the free body diagram.
00:05
And from newton's law, equation of motion for m1 can be written like m1 x1 double dot is equal to minus k1 into x1 minus y minus k2 into x1 minus x2 minus c into x1 dot minus x2 dot.
00:46
We can write m1 x1 double dot is equal double dot plus cx1 dot plus k1 plus k2 into x1 is equal to cx2 dot plus k1 x2 plus sorry k2 x2 plus k1 y.
01:14
Now substitute m, c and k values we will get x1 double dot plus 2x1 dot plus 8x1 is equal to 2x2 dot plus 4x2 plus 4y.
01:43
Now apply laplace transform apply laplace transform for the above equation with zero initial conditions then we will get s square x1 of s plus 2s x1 of s plus 8x1 of s is equal to 2s x2 of s plus 4x2 of s plus 4y of s.
02:21
We can write x1 of s into s square plus 2s plus 8 is is equal to x2 of s into 2s plus 4 plus 4y of s.
02:40
Let us be equation number 1.
02:43
Now equation of motion for m2.
02:47
Equation of motion for m2 can be written as m2 x2 double dot is equal to k2 into x1 minus x2 plus c into x1 dot minus x2 dot.
03:13
That is m2 x2 double dot plus plus cx2 dot plus k2x2 is equal to cx1 dot plus k2x1.
03:28
Now substituting m, c and k values, we can write x2 double dot plus 2x2 dot plus 4x2 is equal to 2x1 dot plus 4x1...