00:01
Hey there, welcome to numerate.
00:03
So we are asked to find the rates at what the energy is delivered.
00:07
So we are going to be working on part a first.
00:11
So for part a, what we have here is that we have the inlet and outlet velocity.
00:20
So let's go ahead and write that down.
00:23
We have the inlet and the outlet velocities in which we're going to be looking for first.
00:34
So hence we have a1.
00:39
Is equivalent to pi r squared so pi 0 .2 squared over 4, which is equivalent to 0 .03142.
00:53
So let's go ahead and do that first thing for a2.
00:58
We have pi times 0 .15 squared divided by 4 is equivalent to 0 .01767.
01:10
We also have v1.
01:14
We take to 0 .075 and divided by the a1, 0 .0342, given us a velocity of 2 .39 meters per second.
01:30
Let's do the same thing for the second velocity here, divided by 767...