Question

1.- Para el circuito mostrado, \(\beta = 25\), \(V_r = 2 V\) y \(k = 1 mA/V^2\) Calcular: a) \(V_o\) si \(V_e = 1 V\) b) \(V_o\) si \(V_e = 10 V\) c) \(V_o\) si \(V_e = 15 V\)

          1.- Para el circuito mostrado, \(\beta = 25\), \(V_r = 2 V\) y \(k = 1 mA/V^2\)
Calcular:
a) \(V_o\) si \(V_e = 1 V\)
b) \(V_o\) si \(V_e = 10 V\)
c) \(V_o\) si \(V_e = 15 V\)

1.- Para el circuito mostrado, β = 25, Vr = 2 V y k = 1 mA/V^2
Calcular:
a) Vo si Ve = 1 V
b) Vo si Ve = 10 V
c) Vo si Ve = 15 V

Added by Alfredo S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Arpit Giri

Step 1

We can use the voltage divider rule to find Vb: Vb = V * (RB2 / (RB1 + RB2)) = 25V * (4kΩ / (6kΩ + 4kΩ)) = 25V * (4kΩ / 10kΩ) = 10V Now, we can find the current flowing through the base of the transistor (Ib) using Ohm's Law: Ib = (Vb - Vy) / RB2 = Show more…

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Thanks for your feedback!

Para el circuito mostrado, V = 25V, Vy = 2V, k = 1mA/V. Calcular: a) Vo si Ve = 1V. b) Vo si Ve = 10V. c) V si Vo = 15V. Vpo = 24V. Vcc = 6V. Ro = 1kÎ©. Rc = 2kÎ©. RB1 = 6kÎ©. R32 = 4kÎ©.