1. \( p=D(x)=80-0.04 x ; p=S(x)=30 e^{0.001 x} \)
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So, we have: \( D(x) = S(x) \) \( 80 - 0.04x = 30e^{0.001x} \) To solve this equation, we can start by isolating the exponential term on one side: \( \frac{80 - 0.04x}{30} = e^{0.001x} \) Show more…
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