1 point Imagine you work for an airline and want to determine the proportion of flights that are more than 10 minutes late. You take a simple random sample of 177 flights and find that 12 of the flights are more than 10 minutes late. Use a \( 92 \% \) confidence level to estimate the proportion of late flights. What is the margin of error? (Show the expression that gives the margin of error with the numbers in place and calculate the value.) Expression: \( 1.75 \sqrt{\frac{(0.068)(0.932)}{778}} \) Margin of error value: type your answer... Note (1): I don't expect you to type in the expression exactly the way I did. Try your best to show me that you know what calculation you are doing (what you are typing in the calculator). Note (2): Round your answer to 3 decimal places.
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The sample proportion (\( \hat{p} \)) is the number of flights that are more than 10 minutes late divided by the total number of flights sampled. Given that 12 out of 177 flights are more than 10 minutes late, the sample proportion is: \[ \hat{p} = \frac{12}{177} Show more…
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