Question

(1 point) Solve for $x$ in each of the following. (a) If $\log_x 512 = \frac{7}{2}$, then $x = 2^{\wedge}(1/8)$ (b) If $8^{9x+8} = 4$, then $x = -22/27$

Name: 1 point solve for x in each of the following a if logx 512 frac72 then x 2wedge18 b if 89x8 4 then x 2227 61862
Uploaded: 2021-05-22T08:20:19-08:00
Duration: 3 min 48 s
Channel: Anas Venkitta
Description: 1 point solve for x in each of the following a if logx 512 frac72 then x 2wedge18 b if 89x8 4 then x 2227 61862

          (1 point)
Solve for $x$ in each of the following.
(a) If $\log_x 512 = \frac{7}{2}$, then $x = 2^{\wedge}(1/8)$
(b) If $8^{9x+8} = 4$, then $x = -22/27$

$1 point solve for x in each of the following a if logx 512 frac72 then x 2wedge18 b if 89x8 4 then x 2227 61862$

Added by Tammy F.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Anas Venkitta

05/22/2021

Step 1

The definition of a logarithm states that if $\log_b a = c$, then $b^c = a$. Applying this definition to the given equation, we have: $x^{\frac{7}{2}} = 512$ Step 2: To solve for $x$, we need to raise both sides of the equation to the power of Show more…

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(1 point) Solve for $x$ in each of the following. (a) If $\log_x 512 = \frac{7}{2}$, then $x = 2^{\wedge}(1/8)$ (b) If $8^{9x+8} = 4$, then $x = -22/27$