00:01
In this problem, i can see that i have the opposite of the quantity of y squared over x to the third all raised the negative 2 power.
00:10
According to order of operations, i should first deal with my exponent.
00:14
So i'm going to distribute this negative 2 into both the numerator and the denominator.
00:21
It's important that you don't forget to distribute to the denominator.
00:24
When we do that, we use our exponent rules that tell us that when you have a power being raised to another power, you multiply the exponents.
00:34
So 2 times negative 2 would give us y to the negative 4th in the numerator, and x to the 3 times negative 2, which is negative 6 in the denominator.
00:46
I now am going to address the fact that we have negative exponents within our parentheses.
00:51
To deal with this, i'm going to write these as separate fractions.
00:55
I'm going to write y to the negative 4th over 1 to show that the y to the negative 4th is in the numerator, times 1 over x to the negative 6th in the denominator.
01:08
I have now broken apart our single fraction into two separate ones...