For segment BC, the internal torque $T_{BC}$ is equal to the applied torque at C, which is $T_C = 400 N \cdot m$.
For segment AB, the internal torque $T_{AB}$ is equal to the sum of the torques at B and C, which is $T_B + T_C = 1200 N \cdot m + 400 N \cdot m =
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