Question

Newton's 2nd law 0.6 y = 0.3732x - 0.0038 0.5 0.4 0.3 w = mg (N) 0.2 0.1 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 a (m/s^2) 9:33 PM Newton's 2nd law 0.6 y = 0.2618x - 0.3821 0.5 0.4 0.3 0.2 0.1 0 2.9 3 3.1 3.2 3.3 3.4 3.5 1/(m+M) (kg)^-1 9:33 PM

          Newton's 2nd law
0.6
y = 0.3732x - 0.0038
0.5
0.4
0.3
w = mg (N)
0.2
0.1
0
0
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
a (m/s^2)
9:33 PM
Newton's 2nd law
0.6
y = 0.2618x - 0.3821
0.5
0.4
0.3
0.2
0.1
0
2.9
3
3.1
3.2
3.3
3.4
3.5
1/(m+M) (kg)^-1
9:33 PM

Newton's 2nd law
0.6
y = 0.3732x - 0.0038
0.5
0.4
0.3
w = mg (N)
0.2
0.1
0
0
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
a (m/s^2)
9:33 PM
Newton's 2nd law
0.6
y = 0.2618x - 0.3821
0.5
0.4
0.3
0.2
0.1
0
2.9
3
3.1
3.2
3.3
3.4
3.5
1/(m+M) (kg)^-1
9:33 PM

Added by Victoria S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Uma Kumari

01/08/2022

Step 1

The equation y = mx + b represents a linear relationship where "m" is the slope of the line and "b" is the y-intercept. If the line passes through the origin, then the y-intercept "b" would be 0. However, in many cases, the line may not pass through the origin and Show more…

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Thanks for your feedback!

1) Should the lines in part 1 and part 2 pass through the origin? Why? Newton's 2nd law 0.6 y=0.3732x-0.0038 0.5 0.4 (N) 0.3 w=mg 0.2 C 0.1 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 a(m/s^2) 9:33PM 0 Newton's 2nd law 0.6 y=0.2618-0.3821 O 0.5 0.4 m/s^2) 0.3 0.2 0.1 0 2.9 3 3.1 3.2 3.3 3.4 3.5 1/m+M)kg^-1 9:33PM