Question

1. Suppose that the massless spring is hanging from the ceiling. When you attached object weighing 30g and spring constant k = 15. From this position you have stretched the spring 5 cm and release. Find the motion of the spring (y) as a function of time. Note: This phenomena can be modelled by a 2$^{nd}$ order ODE as follows: $m \frac{d^2y}{dt^2} + ky = 0$

          1. Suppose that the massless spring is hanging from the ceiling. When you attached object weighing 30g and spring constant k = 15. From this position you have stretched the spring 5 cm and release. Find the motion of the spring (y) as a function of time. Note: This phenomena can be modelled by a 2$^{nd}$ order ODE as follows:
$m \frac{d^2y}{dt^2} + ky = 0$

1. Suppose that the massless spring is hanging from the ceiling. When you attached object weighing 30g and spring constant k = 15. From this position you have stretched the spring 5 cm and release. Find the motion of the spring (y) as a function of time. Note: This phenomena can be modelled by a 2^nd order ODE as follows:
m (d^2y)/(dt^2) + ky = 0

Added by David J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

05/10/2022

Step 1

This equation can be found by taking the derivative of y with respect to time: y'=m(dy/dx) Show more…

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1. Suppose that the massless spring is hanging from the ceiling. When you attached object weighing 30g and of the spring (y) as a function of time. Note: This phenomena can be modelled by a 2nd order ODE as follows: m +ky=0 dt2