Question

1. Suppose the net number of electrons that leave the negative side of a voltage source is $2.35 \times 10^{20}$ electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220\Omega

Name: 1. Suppose the net number of electrons that leave the negative side of a voltage source is 2.35 × 10^20 electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220Ω
Uploaded: 2021-12-31T09:23:41-08:00
Duration: 2 min 5 s
Channel: Pranay Shrivastava
Description: 1. Suppose the net number of electrons that leave the negative side of a voltage source is 2.35 × 10^20 electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220Ω

          1. Suppose the net number of electrons that leave the negative side of a voltage source is $2.35 \times 10^{20}$ electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220\Omega

1. Suppose the net number of electrons that leave the negative side of a voltage source is 2.35 × 10^20 electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220Ω

Added by Linda F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Pranay Shrivastava

12/31/2021

Step 1

The charge of a single electron is 1.602 x 10-19 C. The total charge is then: Q = (2.35 x 1020 electrons) x (1.602 x 10-19 C/electron) = 37.65 C Show more…

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1. Suppose the net number of electrons that leave the negative side of a voltage source is 2.35x1020 electrons and the circuit has been in operation for 1.5 hours. If the voltage source is 12V, then what is the value of the resistor? R = 17220Ω