00:01
Hello, let's have a look on the question.
00:01
So here we have the sample space of red, green, blue and yellow marbles and these are the numbers.
00:07
Now the total number of number of marbles marked 1 is equal to 4.
00:17
Number of marbles marked 2 is equal to 4.
00:22
Number of marbles marked 3 is equal to 3 and the number of marbles that are marked 4 is equal to 2.
00:33
The number of marbles that are marked 5 is equal to 1.
00:38
Now here we need to find out this is for the first part we can say this is the answer for the first part that is we only need to find out the sample space.
00:46
Moving on for the second part we need to find out the probability of for the b part we need to find out the probability of drawing red marble.
00:57
Red marble so this will be equal to total number of total number of red divided by total marble this will be equal to we have three red marbles and total we have 14 marbles.
01:18
This will be the probability for drawing a red marble.
01:22
Moving on we have for the c part the probability of drawing a marble with a number 2 on it.
01:30
Number 2 on it.
01:33
This will be equal to since the number of marbles that are marked 2 is equal to 4.
01:38
So 4 divided by 14 will be equal to 2 divided by 7.
01:42
This is the probability for number 2 marked on a marble.
01:45
Moving on to the d part we need to answer the mutually exclusive.
01:50
So we can so here we can say that no as the mutually exclusive events if occurrence one prevents the occurrence of other in mutually exclusive one event prevents the occurrence of other one occurrence of event 2.
02:19
So here we can say blue ball is not numbered as 2.
02:23
So the both events can happen together as blue ball is not numbered 2.
02:34
So both can happen together.
02:38
Both events can happen together...