00:01
Okay, so i see that you need help with this.
00:04
And the first question is test at the 5 % significance whether the mean gpa of the male is lower than that of the females.
00:14
So mean is of the males, oops, is less than the females.
00:26
And so i'm going to put the average, the sample mean is 2 .34 for the males and the females is 3 .02.
00:37
And the sample standard deviation for the males is 1 .23 and for the females it's 1 .34.
00:46
And the sample size 24 for the male and 26 for the female.
00:57
And so for the significance level, the first thing that you're going to do is you're going to take 23, which is your degree of freedom for the male, and you're going to multiply that by the standard deviation of 1 .23 squared.
01:14
And this is for number one.
01:17
And you're going to add that to the 26 minus 1 is 25.
01:25
And you're going to multiply that by your 1 .34 squared.
01:30
And then you're going to divide that by the 23 plus 25.
01:35
And you're going to get 1 .66.
01:38
And then you're going to take the square root of this.
01:42
And that's going to equal 1 .2885.
01:46
And so then what you're going to do is you're going to take the 1 .2885.
01:51
You're going to multiply that by 124 plus 126.
01:57
And that is going to equal 0 .3647.
02:03
And so then for your degree of freedom, you're going to take 24 plus 26.
02:09
And that's going to equal 50.
02:11
So i'm sorry.
02:14
And then you have to minus 2.
02:15
And then that's 48.
02:17
So that's your combined degree of freedom.
02:19
So to get your t score, it's going to be 2 .0106.
02:29
And that's off the t chart.
02:31
So then you're going to take your difference between your means.
02:35
So you're going to take 2 .34 minus 3 .02.
02:40
And you're going to get negative 0 .68 plus or minus 2 .0106 times 0 .3647.
02:50
And you're going to get a confidence interval of negative 1 .4133 to 0 .0533.
03:01
And because 0 is in between these two variables, that means that there is no difference between the means.
03:11
Between means.
03:15
Testify percent significance, level of significance, whether there's a difference in the proportion of male and female students who prefer the start of the business in barbados.
03:26
Ok, so difference between proportions.
03:33
So we have 0 .45 for the males and then 0 .59 for the females.
03:47
Sample size 24 and then 26 for the females.
03:55
And so what you're going to do first is you're going to take, so this is for two, you're going to take 0 .45 minus 0 .59.
04:06
So that's your male minus your female.
04:08
And you're going to get negative 0 .14.
04:13
You're going to do plus or minus a 95 % confidence interval or 5 % significance level.
04:18
The z score is 1 .96.
04:19
You're going to multiply that by your 0 .45 times 0 .55 divided by 24 plus 0 .59 times 0 .41.
04:35
That's a 4 divided by 26.
04:40
So then you have negative 0 .14 plus or minus 0 .2745.
04:47
And so then you have a confidence interval of negative 0 .4145 to 0 .1345.
05:04
So because 0 is included within the data, there is no difference.
05:11
Ok.
05:11
What is the correlation coefficient for the relationship between the gpa and age of five students in the sample? calculate the coefficient of determination.
05:20
Interpret these values.
05:22
See table three.
05:24
Ok.
05:25
So for this, i'm going to put in my table here.
05:32
So hold on.
05:33
Let me see.
05:34
My x values, i'm just going to type them into my computer.
05:37
3 .94, 3 .15, 2 .53, 3 .21, and 3 .04.
05:43
And then the age values is 21, 35, 42, 23, 32.
05:51
And it wants your coefficient of determination.
05:57
And so, actually, in order to get these values, regression equation.
06:06
And so let me just, i'm going to insert this.
06:18
And put this in right here.
06:26
So this is my table...