00:01
So we have an equation for the position of the y.
00:04
So y of x t equals 1 .5 millimeters.
00:11
This is simply the equation of a wave sign of 157 seconds to the negative first power times t.
00:22
And then minus 41 .9 meters to the negative first power times x.
00:31
And we're going to compare this to the general equation.
00:38
This is equalling a sine of 2 pi times t divided by the period minus x divided by lambda the wavelength.
00:51
So we also know that velocity equals the wavelength times the frequency.
00:57
So for part a when it's asking for the amplitude, the amplitude is simply going to be 1 .50 millimeters.
01:11
To find the wavelength, this is simply going to be equal to 2 pi divided by 41 .9, and this is equaling 0 .150 meters.
01:24
And then for the period, this will simply be 2 pi divided by 157.
01:30
And we're getting that the period is going to be, rather that's, we can say, we can keep this as the period, and then when we want to find the frequency, the frequency is simply the reciprocal of the period...