00:01
Hello students, here we have the coupled pendulum.
00:03
So, coupled pendulum.
00:09
So, for the pendulum we have to derive the lagrangian equation of motion.
00:13
So, first we have to derive the lagrangian equation of motion.
00:28
So, here we can write l equal to p minus p and here p equal to half m y1 dot square plus y2 dot square and p equal to half k del y1 square plus del y2 square.
00:50
So, this is equation 1 and equation 2.
00:55
So, we will get the lagrangian as l equal to half m y1 dot square plus y2 dot square minus 1 by 2 k del y1 square plus del y2 square.
01:17
So, we know that the equation of motion for the lagrangian is d by dt of dou l divided by dou i dot minus dou l divided by dou i equal to 0.
01:38
So, here solving it for y1 we will get for y1 we will get the equation as m y1 double dot plus k del y1 equal to 0.
02:00
Similarly, we will get m y2 double dot plus k del y2 equal to 0.
02:08
So, these are the equation number 4 and 5 and these are the equation of motion for the system.
02:15
Next, we have to write down the kinetic energy matrix as well as the potential energy matrix for the system.
02:25
So, the matrix for i and p.
02:36
So, we know that in the kinetic energy matrix i the diagonal elements contain the mass of masses...