00:01
This first one, we have two resistors in series and a voltage being applied of 10 .1 volts, and we know the resistance in r1 is 9 .9 oms, and r2 is 6 .6 oms.
00:14
And so to find this, the equivalent resistance, since they're in series, is just the combination r1 plus r2.
00:21
So the current in this circuit we can find by just applying oms law.
00:27
And so the current is v divided by the combined resistance or 0 .612 amps.
00:35
And then we can use olm's law again as applied to an individual resistor to find the voltage drop across it.
00:41
So the voltage drop across r1 is i times r1, and we get a voltage drop of 6 .06 volts.
00:50
Now the second problem, i'll pause here so you can take a look at that.
00:57
The second problem, we have three resistors in parallel, and we know the voltage drop across them...