1 the following equation is used to calculate specific heat is used q cmt where t reperesents fi

Step 1: The equation given to calculate specific heat is Q = CmΔT, where ΔT represents the chang

1 the following equation is used to calculate specific heat...

1. The following equation is used to calculate specific heat: Q = CmΔT where ΔT represents the change in temperature (final temperature - initial temperature). 2. A 25 g piece of metal is sitting in a beaker of boiling water. The metal is taken out of the beaker and quickly placed in the calorimeter that contains 85 g of water at 25°C. After the metal has released all of its heat, the temperature of the water is 27.5 °C. What is the specific heat of the metal? mmcmΔTm = mwcwΔTw 2130 J/g°C 0.491 J/g°C 2.30 J/g°C 4135 J/g°C 3. The reaction of a strong acid with a strong base is an exothermic reaction that produces water and heat as products. exothermic reaction endothermic reaction both of them none of them 4. In this table, the elements are arranged in order of increasing atomic number, certain chemical and physical properties repeat periodically. decreasing atomic number increasing atomic number increasing molecular weight decreasing molecular weight 5. In the periodic table, each horizontal row of elements is a period. 6. In the periodic table, each column is a group (or family).

Transcript

00:01 Hello students today will be solving a question in chemistry as you can see from the question this is in fill in the blank slash mcq type of questions so they've given us six questions to solve and they've also given us the option we have to choose the best option that suits the question so let's proceed so the first question they have given us is the following equation is used to calculate specific heat okay so the equation they've given us to calculate the specific heat is c .m.

00:28 Delta t.

00:30 And they're asking us the t represents what? and the options have given us are final temperature, initial temperature, final initial temperature or initial final temperature.

00:40 We know that the delta t in this equation represents the final initial temperature.

00:50 Okay.

00:52 So therefore the answer for the first question is final initial temperature.

00:58 Which is our option c.

01:01 The second question they've given us is a 25 gram piece of metal is sitting in a beaker of boiling water.

01:09 The metal is taken out of the beaker and quickly placed in a calorie meter.

01:14 So a 25 gram piece of metal is in a beaker where boiling water is present.

01:25 And out of nowhere the metal is taken from the beaker and is placed on a.

01:30 Calorie from the beaker the 25 gram metal piece is placed on a calorie meter now the question is after a metal has released all of its heat of temperature the temperature of the water is 27 .5 degrees celsius what is the specific heat of the metal so basically to summarize the question is asking us about find the specific heat of metal and not the combined heat with the water.

02:05 Now if we take the given information given in the question, the mass of metal is 25 grams, the temperature of metal is 100 degrees celsius.

02:19 The mass of water is 85 grams and the specific heat of water is 4 .184 which is the formula and divided by temperature per grams and the temperature of water is 25 degrees celsius and the temperature of fusion is equal to 27 .5 degrees celsius.

02:45 Now what we have to find is the specific heat of the metal.

02:50 So to find this, there is a formula where we have to equate the metal side and the water side.

02:57 So therefore the formula is mass of metal.

03:00 Specific heat of metal multiplied by temperature of fusion minus temperature of water is equal to mass of water multiplied by the specific heat of water whole multiplied by temperature of fusion minus temperature of water now we have to find a specific heat of metal so on taking everything to the right side except the specific heat we'd be getting mass of water, specific heat of water, temperature of fusion minus temperature of water, and mass of metal, temperature of fusion and temperature of water from left inside will be going to the denominator.

03:47 And on substitution of values, we'd be seeing that 85 grams into 4 .184 temperature per grams degrees celsius into 27 .5 degrees celsius minus 25 degrees celsius.

04:08 Whole divided by minus 25 grams as it's coming to the dominator the units are changing and multiplied by 27 .5 minus 100 degrees celsius...

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