00:01
Answer of this question is when 2 -bromobutane, br on reaction with ch3oh, it forms 2 -degree carbocation 2 -degree carbocation, which on reaction with o negative, it forms o double bond o r group.
00:52
So, here this is sn 1 mechanism, which on o and o negative, which on react at that position.
01:12
So, it forms o double bond o.
01:21
So, this is s isomer and when it react on the upper side, so it is it form r isomer.
01:30
So, we are getting racemic mixture of r and s isomer, we are getting racemic mixture, racemic mixture of r and s isomer.
01:58
So, the net optical rotation is 0, net optical rotation is 0, so which is optically inactive, which we can say optically inactive...