Question

1. The number X of customers per day in a local bookstore is normally distributed, with an expected value 560 and standard deviation 120. Evaluate the following probabilities: 1. P(|X - 400| < 100). 2. P(|X - ?x| > 0.5?x). 3. For what m is P(|X - 560| < m = 0.40? 2. The average waiting time at a cash desk in a local supermarket is 8 minutes, with standard deviation 1.7 minutes. Nothing is known about the distribution. 1. Calculate z-scores of 6 and of 10. 2. Estimate the probability that you will wait no more than 10 but at least 6 minutes.

          1. The number X of customers per day in a local bookstore is normally distributed, with an expected value 560 and standard deviation 120. Evaluate the following probabilities:
1. P(|X - 400| < 100).
2. P(|X - ?x| > 0.5?x).
3. For what m is P(|X - 560| < m = 0.40?

2. The average waiting time at a cash desk in a local supermarket is 8 minutes, with standard deviation 1.7 minutes. Nothing is known about the distribution.
1. Calculate z-scores of 6 and of 10.
2. Estimate the probability that you will wait no more than 10 but at least 6 minutes.

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1. The number X of customers per day in a local bookstore is normally distributed, with an expected value 560 and standard deviation 120. Evaluate the following probabilities:
1. P(|X - 400| < 100).
2. P(|X - ?x| > 0.5?x).
3. For what m is P(|X - 560| < m = 0.40?

2. The average waiting time at a cash desk in a local supermarket is 8 minutes, with standard deviation 1.7 minutes. Nothing is known about the distribution.
1. Calculate z-scores of 6 and of 10.
2. Estimate the probability that you will wait no more than 10 but at least 6 minutes.

Added by Amy G.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Sri K

06/28/2022

Step 1

For 6 minutes: \( z = \frac{6 - 8}{1.7} = \frac{-2}{1.7} \approx -1.18 \) For 10 minutes: \( z = \frac{10 - 8}{1.7} = \frac{2}{1.7} \approx 1.18 \) Show more…

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The number X of customers per day in a local bookstore is normally distributed, with an expected value 560 and standard deviation 120. Evaluate the following probabilities: 1. P(|X - 400| < 100). 2. P(|X - μx| > 0.5σx). 3. For what m is P(|X - 560| < m = 0.40? 2. The average waiting time at a cash desk in a local supermarket is 8 minutes, with standard deviation 1.7 minutes. Nothing is known about the distribution. 1. Calculate z-scores of 6 and of 10. 2. Estimate the probability that you will wait no more than 10 but at least 6 minutes.

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