1. There are 10 cats and 8 dogs in a pet shop. Six pets are chosen at random for a visit to a children's hospital. a. What is the probability that less than three of the pets will be dogs? [A /3] b. What is the probability that there are at least five cats? [A /3] c. Determine the expected number of dogs there will be in the group. [A /3]
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Probability that less than three of the pets will be dogs: First, we need to find the total number of ways to choose 6 pets out of 18 (10 cats + 8 dogs). This can be calculated using the combination formula: C(18,6) = 18! / (6! * 12!) = 18*17*16*15*14*13 / Show more…
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