TV channel 2 broadcasts in the frequency range of 54 to 60 MHz. What is the corresponding range of wavelengths?
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Step 1
Given frequency range: 54 MHz to 60 MHz Using the formula lambda = C / F, where C is the speed of light (3 x 10^8 m/s) and F is the frequency. For the maximum frequency (54 MHz): lambda_max = 3 x 10^8 / 54 x 10^6 lambda_max = 5.56 m Show more…
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