00:01
Hello students, given that f of x equal to x cube minus x minus 1 equal to 0 and the initial condition is x0 equal to 1 .5.
00:13
So, we use the newton -raphson method.
00:16
Newton -raphson method formula is xn plus 1 equal to xn minus f of xn divided by f dashed xn.
00:32
So, here f dashed x equal to 3 x square minus 1.
00:40
So, let's perform three iterations.
00:46
So, iteration 1 x1 equal to x0 minus f of x0 divided by f dashed x0.
00:54
So, this is equal to 1 .5 minus 1 .5 whole cube minus 1 .5 minus 1 divided by f dashed xn at 1 .5.
01:10
So, 3 into 1 .5 whole square minus 1.
01:14
So, if we calculate this then we get approximately 1 .29629.
01:24
Similarly, we have x2 is approximately 1 .16730 and x3 is approximately equal to 1 .1468153.
01:38
So, after three iterations.
01:41
So, after three iterations the root of the equation, the root of the equation f of x equal to 0 using the newton -raphson method is approximately x equal to 1 .1468...