00:01
So for a rapidly falling body, we are considering the downward direction as positive.
00:12
So that's positive.
00:15
And then we have the drag force, negative kv squared.
00:20
And the equation we're given is m dv over d t, which is equal to m g minus kv squared.
00:31
Now, as we see here, dvdt is the acceleration, or in other words, change in velocity over time is acceleration.
00:43
So we can relate dvd with acceleration, and mass times acceleration is force.
00:47
So basically, this equation becomes f equals mg minus kv squared.
00:54
So if we consider the starting position as y equal to zero, and then as it goes on, on y increases then for the acceleration we'll have a which is equal to g minus k over m v squared and the reason for that is because f equals m over a so we divide m throughout to get the acceleration now for t equals to zero the displacement y at equal zero is y s y not which is then similarly the velocity v0 is 0 and the acceleration a knot is equal to g minus k over m v squared where v is equal to 0 so that becomes 9 .8 meter per second squared because v is 0 at equal 0 now if we assume that the acceleration is constant over the next interval and so y1, which is the next time interval, basically when time equals to 1, we have y0 plus v0 delta t plus half of a0 delta t whole squared...